o ,1]m @sDdZddlmZmZmZddlmZmZd ddZddZ dgZ dS) zD ``python-future``: pure Python implementation of Python 3 round(). )PYPYPY26 bind_method)DecimalROUND_HALF_EVENNcCsd}|dur d}d}t|dr||S|dkrtdtd| }tr1dtt|vr1t|}t|tr9|}nt sFt |j |t d }n t |j |t d }|rUt|St|S) a See Python 3 documentation: uses Banker's Rounding. Delegates to the __round__ method if for some reason this exists. If not, rounds a number to a given precision in decimal digits (default 0 digits). This returns an int when called with one argument, otherwise the same type as the number. ndigits may be negative. See the test_round method in future/tests/test_builtins.py for examples. FNTr __round__z"negative ndigits not supported yet10numpy)rounding)hasattrrNotImplementedErrorrrreprtypefloat isinstancer from_floatquantizer from_float_26int)numberndigits return_intexponentdr:/usr/lib/python3/dist-packages/future/builtins/newround.pynewround s,     rc Csddl}ddlm}t|ttfrt|S||s||r%tt |S| d|dkr0d}nd}t | \}}dd}||d}||t |d|| }|S) aConverts a float to a decimal number, exactly. Note that Decimal.from_float(0.1) is not the same as Decimal('0.1'). Since 0.1 is not exactly representable in binary floating point, the value is stored as the nearest representable value which is 0x1.999999999999ap-4. The exact equivalent of the value in decimal is 0.1000000000000000055511151231257827021181583404541015625. >>> Decimal.from_float(0.1) Decimal('0.1000000000000000055511151231257827021181583404541015625') >>> Decimal.from_float(float('nan')) Decimal('NaN') >>> Decimal.from_float(float('inf')) Decimal('Infinity') >>> Decimal.from_float(-float('inf')) Decimal('-Infinity') >>> Decimal.from_float(-0.0) Decimal('-0') rN)_dec_from_tripleg?cSs |dkrttt|dSdS)Nr)lenbinabs)rrrr bit_length\sz!from_float_26..bit_length)mathdecimalrrrlongrisinfisnanr copysignr"as_integer_ratiostr) f_mathrsignnrr#kresultrrrr:s   r)N) __doc__ future.utilsrrrr&rrrr__all__rrrrs  . ,